Posted by kfatima [send private reply] at November 19, 2002, 11:35:51 PM

hi all,
i am new here and i have a question about the scheme language, i am getting this 'out of bound variable' error for one of my functions, can someone tell me what possibly can be causing it?
i would post part of my code if needed for more clarification
thanks a lot

Posted by buzgub [send private reply] at November 19, 2002, 11:56:14 PM

if arrays or similar are involved, I'd guess that you're trying to access an element that doesn't exist.

I'm no scheme guru, though. Perhaps unknown_lamer can tell you about this error.

Posted by ItinitI [send private reply] at November 20, 2002, 09:23:07 PM

Ugh, yeah, unknown_lamer is the scheme master here.

Posted by unknown_lamer [send private reply] at November 20, 2002, 09:29:40 PM

Please post the body of the function. I will answer your schemely questions.

Posted by CDR700 [send private reply] at November 21, 2002, 11:07:37 AM

Is unknown_lamer the scheme guru around here,i thought so,great site by the way - make it ISO compliant and it will be even better?

Posted by kfatima [send private reply] at November 21, 2002, 02:33:11 PM

thanks unknown_lamer for the relpy.
ok i am posting the code now. basically it is the hash-division-method, that is supposed to return a function.

;; value of parameter "size" should be a prime number
(define gen-hash-division-method
(lambda (size) ;; range of values: 0..size-1
(lambda (x)(modulo key(w) size))))

(define key
(lambda (w)
(if (null? (cdr w)) (ctv (car w))
(* (ctv (car w)) (key (cdr w))))))
;key takes in the word as a list and return the ctv of it
so (key '(a b c)) -> returns 12 and so on.
so the division methods takes in the number generated by the key function and takes modulus of that and size
but i am getting unbound variables error in the division function . any kind of help would be appreciated.

Posted by unknown_lamer [send private reply] at November 21, 2002, 05:48:25 PM

(define gen-hash-division-method
(lambda (size) ;; range of values: 0..size-1
(lambda (x)(modulo (key '(w)) size)))) 

You wrote "key(w)" instead of "(key '(w))". Remember to put parens around procedure calls.