Hello,
Please help me understand the order of evaluation in the following code. Although it may not look practical but for me is to understand the rules. I am using MS compiler. The result from Java is: x=41, i=7, while from C is: x=36, i=7
I appreciate your help. Thanks
#include <stdio.h>
main()
{
int x = 0, i = 5;
x = i - ++i + (i++) * i;
printf("x=%d, i=%d\n", x, i);
}

not exactly what I call clean code...

my guess would be x = 5 - 6 + 6 * 7, which results in 41.

although, (i - ++i) seems to evaluate to 0. and (i++) * i[assuming i = 6] results in 36. Guess someone was smoking something bad. (And the author of the above isn't much better IMHO)

I would guess that using a ++/-- operator in the same expression with a second use of the same variable is not well defined across compilers.

We had all sorts of fun with such ambiguities in compilers class last semester. I'd avoid multiple uses of those side-effecting operators if I were you. It's really not worth learning the details of your compiler.

Undefined.

http://www.eskimo.com/~scs/C-faq/q3.2.html